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Joules to Foot Pounds

The joule is the SI unit of energy, defined as the work done by one newton over one meter. A foot-pound is the energy of one pound of force acting over one foot, used to describe bolt torque and impact energy in the US. 1 J equals ≈0.737562 ft·lbf, so converting between them is a matter of multiplying by that fixed factor — type any value into the converter below and both sides update instantly as you type.

Both units belong to energy, measured here against energy's base unit (J) — every other energy unit on this site converts through that same reference point, which is why the table below can also be read as a quick cross-check against nearby values.

Formula

ft·lbf = J × ≈0.737562

J = ft·lbf × ≈1.35582

Worked example: 5 J × ≈0.737562 = ≈3.68781 ft·lbf.

Conversion table

Joule (J)Foot-pound (ft·lbf)
1 J≈0.737562 ft·lbf
2 J≈1.47512 ft·lbf
3 J≈2.21269 ft·lbf
5 J≈3.68781 ft·lbf
10 J≈7.37562 ft·lbf
20 J≈14.7512 ft·lbf
25 J≈18.4391 ft·lbf
50 J≈36.8781 ft·lbf
100 J≈73.7562 ft·lbf
250 J≈184.391 ft·lbf
500 J≈368.781 ft·lbf
1,000 J≈737.562 ft·lbf

Frequently asked

How many Foot-pounds in a joule?
1 J equals ≈0.737562 ft·lbf.
How do I convert Joules to Foot-pounds?
Multiply the value in J by ≈0.737562 to get ft·lbf. The converter above does this instantly as you type.
Is the conversion exact?
Yes — Joule and Foot-pound are both defined by a fixed conversion factor to energy's base unit (J), so the result shown is exact to the precision displayed, not an approximation.

Reverse conversion

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